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  BigEvilDan  
stripcreator donor

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by BigEvilDan
10-28-02
...so, what is the characteristic polynomial for again?
If you solve for the unknown, you get the eigenvalues of A.
And I can substitute those into the other equation to get the eigenvectors, which make up P.
You got it.
Okay, one more question. What is six times five?
Let me get my calculator...
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